Skip to main content

First Come First Serve (FCFS) Page replacement algorithm in C Programming

#include< stdio.h>
#include< conio.h>
int fsize;
int frm[15];
void display();
void main()
{
 int pg[100],nPage,i,j,pf=0,top=-1,temp,flag=0;
 clrscr();
 printf("\n Enter frame size:");
 scanf("%d",&fsize);
 printf("\n Enter number of pages:");
 scanf("%d",&nPage);

 for(i=0;i< nPage;i++)
 {
  printf("\n Enter page[%d]:",i+1);
  scanf("%d",&pg[i]);
 }
   for(i=0;i< fsize;i++)
    frm[i]=-1;
printf("\n page | \t Frame content ");
printf("\n--------------------------------------");
for(j=0;j< nPage;j++)
{
 flag=0;
  for(i=0;i< fsize;i++)
  {
   if(frm[i]==pg[j])
   {
    flag=1;
    break;
   }
  }


  if(flag==0)
  {
   if(top==fsize-1)
   {
    top=-1;
   }
   pf++;
   top++;
   frm[top]=pg[j];
  }
 printf("\n %d    |",pg[j]);
 display();
}
  printf("\n--------------------------------------");
 printf("\n total page fault:%d",pf);
getch();
}
void display()
{
 int i;
 for(i=0;i< fsize;i++)
  printf("\t %d",frm[i]);
}

OUTPUT
Enter frame size:3

 Enter number of pages:12

 Enter page[1]:1
 Enter page[2]:2
 Enter page[3]:3
 Enter page[4]:4
 Enter page[5]:1
 Enter page[6]:2
 Enter page[7]:5
 Enter page[8]:1
 Enter page[9]:2
 Enter page[10]:3
 Enter page[11]:4
 Enter page[12]:5

 page |          Frame content
--------------------------------------
 1    |  1       -1      -1
 2    |  1       2       -1
 3    |  1       2       3
 4    |  4       2       3
 1    |  4       1       3
 2    |  4       1       2
 5    |  5       1       2
 1    |  5       1       2
 2    |  5       1       2
 3    |  5       3       2
 4    |  5       3       4
 5    |  5       3       4
--------------------------------------
 total page fault:9

Comments

Popular posts from this blog

MVT (Multiprogramming Variable Task) in C Programming

#include< stdio.h> #include< conio.h> void main() { int i,os_m,nPage,total,pg[25]; clrscr(); printf("\nEnter total memory size:"); scanf("%d",&total); printf("\nEnter memory for OS:"); scanf("%d",&os_m); printf("\nEnter no. of pages:"); scanf("%d",&nPage); for(i=0;i< nPage;i++) { printf("Enter size of page[%d]:",i+1); scanf("%d",&pg[i]); } total=total-os_m; for(i=0;i< nPage;i++) { if(total>=pg[i]) { printf("\n Allocate page %d",i+1); total=total-pg[i]; } else printf("\n page %d is not allocated due to insufficient memory.",i+1); } printf("\n External Fragmentation is:%d",total); getch(); } OUTPUT Enter total memory size:1024 Enter memory for OS:256 Enter no. of pages:4 Enter size of page[1]:128 Enter size of page[2]:512 Enter size of page[3]:64 Enter size of page[4]:512 Allocate page 1 Al

implement Rail fence cipher in Java

// File Name: RailFence.java import java.util.*; class RailFenceBasic{ int depth; String Encryption(String plainText,int depth)throws Exception { int r=depth,len=plainText.length(); int c=len/depth; char mat[][]=new char[r][c]; int k=0; String cipherText=""; for(int i=0;i< c;i++) { for(int j=0;j< r;j++) { if(k!=len) mat[j][i]=plainText.charAt(k++); else mat[j][i]='X'; } } for(int i=0;i< r;i++) { for(int j=0;j< c;j++) { cipherText+=mat[i][j]; } } return cipherText; } String Decryption(String cipherText,int depth)throws Exception { int r=depth,len=cipherText.length(); int c=len/depth; char mat[][]=new char[r][c]; int k=0; String plainText=""; for(int i=0;i< r;i++) { for(int j=0;j< c;j++) { mat[i][j]=cipherText.charAt(k++); } } for(int i=0;i< c;i++) { for(int j=0;j< r;j++) { plainText+=mat[j][i]; } }

Deadlock Prevention using Banker’s Algorithm in C Programming

#include< stdio.h> #include< conio.h> void main() { int allocated[15][15],max[15][15],need[15][15],avail[15],tres[15],work[15],flag[15]; int pno,rno,i,j,prc,count,t,total; count=0; clrscr(); printf("\n Enter number of process:"); scanf("%d",&pno); printf("\n Enter number of resources:"); scanf("%d",&rno); for(i=1;i< =pno;i++) { flag[i]=0; } printf("\n Enter total numbers of each resources:"); for(i=1;i<= rno;i++) scanf("%d",&tres[i]); printf("\n Enter Max resources for each process:"); for(i=1;i<= pno;i++) { printf("\n for process %d:",i); for(j=1;j<= rno;j++) scanf("%d",&max[i][j]); } printf("\n Enter allocated resources for each process:"); for(i=1;i<= pno;i++) { printf("\n for process %d:",i); for(j=1;j<= rno;j++) scanf("%d",&allocated[i][j]); } printf("\n avai